This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
6D16 = 6 D = 6(=0110) D(=1101) = 11011012
the Final answer: 6D16 = 11011012
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
6∙161+13∙160 = 6∙16+13∙1 = 96+13 = 10910
got It: 6D16 =10910
Translate the number 10910 в binary like this:
the Integer part of the number is divided by the base of the new number system:
109 | 2 | | | | | | |
-108 | 54 | 2 | | | | | |
1 | -54 | 27 | 2 | | | | |
| 0 | -26 | 13 | 2 | | | |
| | 1 | -12 | 6 | 2 | | |
| | | 1 | -6 | 3 | 2 | |
| | | | 0 | -2 | 1 | |
| | | | | 1 | | |
 |
the result of the conversion was:
10910 = 11011012
the Final answer: 6D16 = 11011012