Transfer 01101010 from binary in hexadecimal number system

You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.

to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.

					.
0	0	1	0	1	1	0	twos-complement
					-	1	-1 bit
1	0	1	0	1	0	1	ones complement
1	1	0	1	0	1	0	direct code

got It:1101010

This transfer is possible in two ways: direct transfer and using the decimal system.

first, let\'s make a direct transfer.

Fill in the number with missing zeros on the left

let\'s do a direct translation from binary to hexadecimal like this:

01101010₂ = 0110 1010 = 0110₍₌₆₎ 1010_(=A) = 6A₁₆

the Final answer: 01101010₂ = 6A₁₆

now let\'s make the transfer using the decimal system.

let\'s translate to decimal like this:

0∙2⁷+1∙2⁶+1∙2⁵+0∙2⁴+1∙2³+0∙2²+1∙2¹+0∙2⁰ = 0∙128+1∙64+1∙32+0∙16+1∙8+0∙4+1∙2+0∙1 = 0+64+32+0+8+0+2+0 = 106₁₀

got It: 01101010₂ =106₁₀

Translate the number 106₁₀ в hexadecimal like this:

the Integer part of the number is divided by the base of the new number system:

106	16
-96	6
A

the result of the conversion was:

106₁₀ = 6A₁₆

the Final answer: 01101010₂ = 6A₁₆

0
(	)	^	←
C	±	÷	X
7	8	9	-
4	5	6	+
1	2	3	=
0		.	=