You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| | | | | | | | |
0 | 1 | 0 | 0 | 0 | 0 | 0 | 1 | twos-complement |
| | | | | | - | 1 | -1 bit |
1 | 1 | 0 | 0 | 0 | 0 | 0 | 0 | ones complement |
1 | 0 | 1 | 1 | 1 | 1 | 1 | 1 | direct code |
got It:10111111
let\'s translate to decimal like this:
1∙27+0∙26+1∙25+1∙24+1∙23+1∙22+1∙21+1∙20 = 1∙128+0∙64+1∙32+1∙16+1∙8+1∙4+1∙2+1∙1 = 128+0+32+16+8+4+2+1 = 19110
got It: 101111112 =19110