You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| | | | | | | | |
0 | 1 | 1 | 1 | 0 | 1 | 0 | 1 | twos-complement |
| | | | | | - | 1 | -1 bit |
1 | 1 | 1 | 1 | 0 | 1 | 0 | 0 | ones complement |
1 | 0 | 0 | 0 | 1 | 0 | 1 | 1 | direct code |
got It:10001011
let\'s translate to decimal like this:
1∙27+0∙26+0∙25+0∙24+1∙23+0∙22+1∙21+1∙20 = 1∙128+0∙64+0∙32+0∙16+1∙8+0∙4+1∙2+1∙1 = 128+0+0+0+8+0+2+1 = 13910
got It: 100010112 =13910