You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| | | | | | . | | |
1 | 0 | 1 | 1 | 0 | 1 | 1 | 0 | twos-complement |
| | | | | | - | 1 | -1 bit |
1 | 0 | 1 | 1 | 0 | 1 | 0 | 1 | ones complement |
1 | 1 | 0 | 0 | 1 | 0 | 1 | 0 | direct code |
got It:11001010
let\'s translate to decimal like this:
1∙27+1∙26+0∙25+0∙24+1∙23+0∙22+1∙21+0∙20 = 1∙128+1∙64+0∙32+0∙16+1∙8+0∙4+1∙2+0∙1 = 128+64+0+0+8+0+2+0 = 20210
got It: 110010102 =20210