You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| | | | | | | | | | | | | | |
0 | 1 | 1 | 1 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | twos-complement |
| | | | | | | | | | | | - | 1 | -1 bit |
1 | 1 | 1 | 1 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 0 | 1 | 0 | ones complement |
1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 1 | 0 | 1 | direct code |
got It:10000001000101
let\'s translate to decimal like this:
1∙213+0∙212+0∙211+0∙210+0∙29+0∙28+0∙27+1∙26+0∙25+0∙24+0∙23+1∙22+0∙21+1∙20 = 1∙8192+0∙4096+0∙2048+0∙1024+0∙512+0∙256+0∙128+1∙64+0∙32+0∙16+0∙8+1∙4+0∙2+1∙1 = 8192+0+0+0+0+0+0+64+0+0+0+4+0+1 = 826110
got It: 100000010001012 =826110