You specified that your number is in the additional code. For further conversion, you need to get a direct number code. Therefore, let\'s perform the conversion from additional code to direct code.
to do this, first perform the conversion from the additional code to the reverse by subtracting 1 bit, then get the direct code by inverting all the bits except the signed one.
| | | | | | | | | | | | | | |
1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 1 | 0 | 1 | twos-complement |
| | | | | | | | | | | | - | 1 | -1 bit |
1 | 0 | 0 | 0 | 0 | 0 | 0 | 1 | 0 | 0 | 0 | 1 | 0 | 0 | ones complement |
1 | 1 | 1 | 1 | 1 | 1 | 1 | 0 | 1 | 1 | 1 | 0 | 1 | 1 | direct code |
got It:11111110111011
let\'s translate to decimal like this:
1∙213+1∙212+1∙211+1∙210+1∙29+1∙28+1∙27+0∙26+1∙25+1∙24+1∙23+0∙22+1∙21+1∙20 = 1∙8192+1∙4096+1∙2048+1∙1024+1∙512+1∙256+1∙128+0∙64+1∙32+1∙16+1∙8+0∙4+1∙2+1∙1 = 8192+4096+2048+1024+512+256+128+0+32+16+8+0+2+1 = 1631510
got It: 111111101110112 =1631510