Transfer 2ED from hexadecimal in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

First we will perform the translation through the decimal system

let\'s translate to decimal like this:

2∙162+14∙161+13∙160 = 2∙256+14∙16+13∙1 = 512+224+13 = 74910

got It: 2ED16 =74910

Translate the number 74910 в octal like this:

the Integer part of the number is divided by the base of the new number system:

7498
-744938
5-88118
5-81
3
Перевод чисел из одной системы счисления в другую

the result of the conversion was:

74910 = 13558
the Final answer: 2ED16 = 13558

Now we will perform a direct translation.

let\'s do a direct translation from hexadecimal to binary like this:

2ED16 = 2 E D = 2(=0010) E(=1110) D(=1101) = 10111011012

the Final answer: 2ED16 = 10111011012

Fill in the number with missing zeros on the left

let\'s make a direct translation from binary to post-binary like this:

0010111011012 = 001 011 101 101 = 001(=1) 011(=3) 101(=5) 101(=5) = 13558

the Final answer: 2ED16 = 13558
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