Transfer 1101100110.0101 from binary in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

first, let\'s make a direct transfer.

Fill in the number with missing zeros on the left

Fill in the number with missing zeros on the right

let\'s make a direct translation from binary to post-binary like this:

001101100110.0101002 = 001 101 100 110. 010 100 = 001(=1) 101(=5) 100(=4) 110(=6). 010(=2) 100(=4) = 1546.248

the Final answer: 1101100110.01012 = 1546.248

now let\'s make the transfer using the decimal system.

let\'s translate to decimal like this:

0∙211+0∙210+1∙29+1∙28+0∙27+1∙26+1∙25+0∙24+0∙23+1∙22+1∙21+0∙20+0∙2-1+1∙2-2+0∙2-3+1∙2-4+0∙2-5+0∙2-6 = 0∙2048+0∙1024+1∙512+1∙256+0∙128+1∙64+1∙32+0∙16+0∙8+1∙4+1∙2+0∙1+0∙0.5+1∙0.25+0∙0.125+1∙0.0625+0∙0.03125+0∙0.015625 = 0+0+512+256+0+64+32+0+0+4+2+0+0+0.25+0+0.0625+0+0 = 870.312510

got It: 001101100110.0101002 =870.312510

Translate the number 870.312510 в octal like this:

the Integer part of the number is divided by the base of the new number system:

8708
-8641088
6-104138
4-81
5
Перевод чисел из одной системы счисления в другую

the Fractional part of the number is multiplied by the base of the new number system:

 Transferring numbers from one number system to another
0.3125*8
2.5*8
4.0*8

the result of the conversion was:

870.312510 = 1546.248
the Final answer: 1101100110.01012 = 1546.248
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