This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from hexadecimal to binary like this:
0.7E316 = 0. 7 E 3 = 0(=0000). 7(=0111) E(=1110) 3(=0011) = .0111111000112
the Final answer: 0.7E316 = .0111111000112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙160+7∙16-1+14∙16-2+3∙16-3 = 0∙1+7∙0.0625+14∙0.00390625+3∙0.000244140625 = 0+0.4375+0.0546875+0.000732421875 = 0.49291992187510
got It: 0.7E316 =0.49291992187510
Translate the number 0.49291992187510 в binary like this:
the Fractional part of the number is multiplied by the base of the new number system:
 |
0. | 492919921875*2 |
0 | .98584*2 |
1 | .97168*2 |
1 | .94336*2 |
1 | .88672*2 |
1 | .77344*2 |
1 | .54688*2 |
1 | .09375*2 |
0 | .1875*2 |
0 | .375*2 |
0 | .75*2 |
the result of the conversion was:
0.49291992187510 = 0.01111110002
the Final answer: 0.7E316 = 0.01111110002