This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
11∙163+2∙162+13∙161+4∙160+2∙16-1+10∙16-2 = 11∙4096+2∙256+13∙16+4∙1+2∙0.0625+10∙0.00390625 = 45056+512+208+4+0.125+0.0390625 = 45780.164062510
got It: B2D4.2A16 =45780.164062510
Translate the number 45780.164062510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
45780 | 8 | | | | | |
-45776 | 5722 | 8 | | | | |
4 | -5720 | 715 | 8 | | | |
| 2 | -712 | 89 | 8 | | |
| | 3 | -88 | 11 | 8 | |
| | | 1 | -8 | 1 | |
| | | | 3 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 1640625*8 |
1 | .3125*8 |
2 | .5*8 |
4 | .0*8 |
the result of the conversion was:
45780.164062510 = 131324.1248
the Final answer: B2D4.2A16 = 131324.1248
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
B2D4.2A16 = B 2 D 4. 2 A = B(=1011) 2(=0010) D(=1101) 4(=0100). 2(=0010) A(=1010) = 1011001011010100.00101012
the Final answer: B2D4.2A16 = 1011001011010100.00101012
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001011001011010100.0010101002 = 001 011 001 011 010 100. 001 010 100 = 001(=1) 011(=3) 001(=1) 011(=3) 010(=2) 100(=4). 001(=1) 010(=2) 100(=4) = 131324.1248
the Final answer: B2D4.2A16 = 131324.1248