This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
010001.1012 = 010 001. 101 = 010(=2) 001(=1). 101(=5) = 21.58
the Final answer: 10001.1012 = 21.58
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+1∙24+0∙23+0∙22+0∙21+1∙20+1∙2-1+0∙2-2+1∙2-3 = 0∙32+1∙16+0∙8+0∙4+0∙2+1∙1+1∙0.5+0∙0.25+1∙0.125 = 0+16+0+0+0+1+0.5+0+0.125 = 17.62510
got It: 010001.1012 =17.62510
Translate the number 17.62510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
17 | 8 | |
-16 | 2 | |
1 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 625*8 |
5 | .0*8 |
the result of the conversion was:
17.62510 = 21.58
the Final answer: 10001.1012 = 21.58