This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
15∙161+10∙160+15∙16-1+10∙16-2 = 15∙16+10∙1+15∙0.0625+10∙0.00390625 = 240+10+0.9375+0.0390625 = 250.976562510
got It: FA.FA16 =250.976562510
Translate the number 250.976562510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
250 | 8 | | |
-248 | 31 | 8 | |
2 | -24 | 3 | |
| 7 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 9765625*8 |
7 | .8125*8 |
6 | .5*8 |
4 | .0*8 |
the result of the conversion was:
250.976562510 = 372.7648
the Final answer: FA.FA16 = 372.7648
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
FA.FA16 = F A. F A = F(=1111) A(=1010). F(=1111) A(=1010) = 11111010.11111012
the Final answer: FA.FA16 = 11111010.11111012
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
011111010.1111101002 = 011 111 010. 111 110 100 = 011(=3) 111(=7) 010(=2). 111(=7) 110(=6) 100(=4) = 372.7648
the Final answer: FA.FA16 = 372.7648