This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0010001012 = 001 000 101 = 001(=1) 000(=0) 101(=5) = 1058
the Final answer: 10001012 = 1058
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+0∙27+1∙26+0∙25+0∙24+0∙23+1∙22+0∙21+1∙20 = 0∙256+0∙128+1∙64+0∙32+0∙16+0∙8+1∙4+0∙2+1∙1 = 0+0+64+0+0+0+4+0+1 = 6910
got It: 0010001012 =6910
Translate the number 6910 в octal like this:
the Integer part of the number is divided by the base of the new number system:
69 | 8 | | |
-64 | 8 | 8 | |
5 | -8 | 1 | |
| 0 | | |
|
the result of the conversion was:
6910 = 1058
the Final answer: 10001012 = 1058