This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0010100111011012 = 001 010 011 101 101 = 001(=1) 010(=2) 011(=3) 101(=5) 101(=5) = 123558
the Final answer: 10100111011012 = 123558
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙214+0∙213+1∙212+0∙211+1∙210+0∙29+0∙28+1∙27+1∙26+1∙25+0∙24+1∙23+1∙22+0∙21+1∙20 = 0∙16384+0∙8192+1∙4096+0∙2048+1∙1024+0∙512+0∙256+1∙128+1∙64+1∙32+0∙16+1∙8+1∙4+0∙2+1∙1 = 0+0+4096+0+1024+0+0+128+64+32+0+8+4+0+1 = 535710
got It: 0010100111011012 =535710
Translate the number 535710 в octal like this:
the Integer part of the number is divided by the base of the new number system:
| 5357 | 8 | | | | |
| -5352 | 669 | 8 | | | |
| 5 | -664 | 83 | 8 | | |
| 5 | -80 | 10 | 8 | |
| | 3 | -8 | 1 | |
| | | 2 | | |
 |
the result of the conversion was:
535710 = 123558
the Final answer: 10100111011012 = 123558