This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s make a direct translation from binary to post-binary like this:
1111012 = 111 101 = 111(=7) 101(=5) = 758
the Final answer: 1111012 = 758
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
1∙25+1∙24+1∙23+1∙22+0∙21+1∙20 = 1∙32+1∙16+1∙8+1∙4+0∙2+1∙1 = 32+16+8+4+0+1 = 6110
got It: 1111012 =6110
Translate the number 6110 в octal like this:
the Integer part of the number is divided by the base of the new number system:
61 | 8 | |
-56 | 7 | |
5 | | |
|
the result of the conversion was:
6110 = 758
the Final answer: 1111012 = 758