# Transfer 2B3C4F.5 from hexadecimal in binary number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

first, let\'s make a direct transfer.

let\'s do a direct translation from hexadecimal to binary like this:

2B3C4F.516 = 2 B 3 C 4 F. 5 = 2(=0010) B(=1011) 3(=0011) C(=1100) 4(=0100) F(=1111). 5(=0101) = 1010110011110001001111.01012

the Final answer: 2B3C4F.516 = 1010110011110001001111.01012

now let\'s make the transfer using the decimal system.

let\'s translate to decimal like this:

2∙165+11∙164+3∙163+12∙162+4∙161+15∙160+5∙16-1 = 2∙1048576+11∙65536+3∙4096+12∙256+4∙16+15∙1+5∙0.0625 = 2097152+720896+12288+3072+64+15+0.3125 = 2833487.312510

got It: 2B3C4F.516 =2833487.312510

Translate the number 2833487.312510 в binary like this:

the Integer part of the number is divided by the base of the new number system:

 2833487 2 -2833486 1416743 2 1 -1416742 708371 2 1 -708370 354185 2 1 -354184 177092 2 1 -177092 88546 2 0 -88546 44273 2 0 -44272 22136 2 1 -22136 11068 2 0 -11068 5534 2 0 -5534 2767 2 0 -2766 1383 2 1 -1382 691 2 1 -690 345 2 1 -344 172 2 1 -172 86 2 0 -86 43 2 0 -42 21 2 1 -20 10 2 1 -10 5 2 0 -4 2 2 1 -2 1 0

the Fractional part of the number is multiplied by the base of the new number system:

 0. 3125*2 0 .625*2 1 .25*2 0 .5*2 1 .0*2

the result of the conversion was:

2833487.312510 = 1010110011110001001111.01012
the Final answer: 2B3C4F.516 = 1010110011110001001111.01012
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