This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
8∙162+7∙161+9∙160 = 8∙256+7∙16+9∙1 = 2048+112+9 = 216910
got It: 87916 =216910
Translate the number 216910 в octal like this:
the Integer part of the number is divided by the base of the new number system:
2169 | 8 | | | |
-2168 | 271 | 8 | | |
1 | -264 | 33 | 8 | |
| 7 | -32 | 4 | |
| | 1 | | |
 |
the result of the conversion was:
216910 = 41718
the Final answer: 87916 = 41718
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
87916 = 8 7 9 = 8(=1000) 7(=0111) 9(=1001) = 1000011110012
the Final answer: 87916 = 1000011110012
let\'s make a direct translation from binary to post-binary like this:
1000011110012 = 100 001 111 001 = 100(=4) 001(=1) 111(=7) 001(=1) = 41718
the Final answer: 87916 = 41718