This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
6∙163+1∙162+0∙161+8∙160+4∙16-1+12∙16-2 = 6∙4096+1∙256+0∙16+8∙1+4∙0.0625+12∙0.00390625 = 24576+256+0+8+0.25+0.046875 = 24840.29687510
got It: 6108.4C16 =24840.29687510
Translate the number 24840.29687510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
24840 | 8 | | | | |
-24840 | 3105 | 8 | | | |
0 | -3104 | 388 | 8 | | |
| 1 | -384 | 48 | 8 | |
| | 4 | -48 | 6 | |
| | | 0 | | |
 |
the Fractional part of the number is multiplied by the base of the new number system:
 |
0. | 296875*8 |
2 | .375*8 |
3 | .0*8 |
the result of the conversion was:
24840.29687510 = 60410.238
the Final answer: 6108.4C16 = 60410.238
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
6108.4C16 = 6 1 0 8. 4 C = 6(=0110) 1(=0001) 0(=0000) 8(=1000). 4(=0100) C(=1100) = 110000100001000.0100112
the Final answer: 6108.4C16 = 110000100001000.0100112
let\'s make a direct translation from binary to post-binary like this:
110000100001000.0100112 = 110 000 100 001 000. 010 011 = 110(=6) 000(=0) 100(=4) 001(=1) 000(=0). 010(=2) 011(=3) = 60410.238
the Final answer: 6108.4C16 = 60410.238