This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
6∙83+4∙82+7∙81+3∙80 = 6∙512+4∙64+7∙8+3∙1 = 3072+256+56+3 = 338710
got It: 64738 =338710
Translate the number 338710 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
3387 | 16 | | |
-3376 | 211 | 16 | |
B | -208 | D | |
| 3 | | |
 |
the result of the conversion was:
338710 = D3B16
the Final answer: 64738 = D3B16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
64738 = 6 4 7 3 = 6(=110) 4(=100) 7(=111) 3(=011) = 1101001110112
the Final answer: 64738 = 1101001110112
let\'s do a direct translation from binary to hexadecimal like this:
1101001110112 = 1101 0011 1011 = 1101(=D) 0011(=3) 1011(=B) = D3B16
the Final answer: 1101001110118 = D3B16