# Transfer C6.A6 from hexadecimal in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

First we will perform the translation through the decimal system

let\'s translate to decimal like this:

12∙161+6∙160+10∙16-1+6∙16-2 = 12∙16+6∙1+10∙0.0625+6∙0.00390625 = 192+6+0.625+0.0234375 = 198.648437510

got It: C6.A616 =198.648437510

Translate the number 198.648437510 в octal like this:

the Integer part of the number is divided by the base of the new number system:

 198 8 -192 24 8 6 -24 3 0

the Fractional part of the number is multiplied by the base of the new number system:

 0. 6484375*8 5 .1875*8 1 .5*8 4 .0*8

the result of the conversion was:

198.648437510 = 306.5148
the Final answer: C6.A616 = 306.5148

Now we will perform a direct translation.

let\'s do a direct translation from hexadecimal to binary like this:

C6.A616 = C 6. A 6 = C(=1100) 6(=0110). A(=1010) 6(=0110) = 11000110.10100112

the Final answer: C6.A616 = 11000110.10100112

Fill in the number with missing zeros on the left

Fill in the number with missing zeros on the right

let\'s make a direct translation from binary to post-binary like this:

011000110.1010011002 = 011 000 110. 101 001 100 = 011(=3) 000(=0) 110(=6). 101(=5) 001(=1) 100(=4) = 306.5148

the Final answer: C6.A616 = 306.5148
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