This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
000110.1002 = 000 110. 100 = 000(=0) 110(=6). 100(=4) = 06.48
the Final answer: 0110.1002 = 06.48
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙25+0∙24+0∙23+1∙22+1∙21+0∙20+1∙2-1+0∙2-2+0∙2-3 = 0∙32+0∙16+0∙8+1∙4+1∙2+0∙1+1∙0.5+0∙0.25+0∙0.125 = 0+0+0+4+2+0+0.5+0+0 = 6.510
got It: 000110.1002 =6.510
Translate the number 6.510 в octal like this:
the Fractional part of the number is multiplied by the base of the new number system:
 |
0. | 5*8 |
4 | .0*8 |
the result of the conversion was:
6.510 = 6.48
the Final answer: 0110.1002 = 6.48