This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0110101112 = 011 010 111 = 011(=3) 010(=2) 111(=7) = 3278
the Final answer: 110101112 = 3278
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙28+1∙27+1∙26+0∙25+1∙24+0∙23+1∙22+1∙21+1∙20 = 0∙256+1∙128+1∙64+0∙32+1∙16+0∙8+1∙4+1∙2+1∙1 = 0+128+64+0+16+0+4+2+1 = 21510
got It: 0110101112 =21510
Translate the number 21510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
215 | 8 | | |
-208 | 26 | 8 | |
7 | -24 | 3 | |
| 2 | | |
 |
the result of the conversion was:
21510 = 3278
the Final answer: 110101112 = 3278