Transfer 11010111 from binary in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

first, let\'s make a direct transfer.

Fill in the number with missing zeros on the left

let\'s make a direct translation from binary to post-binary like this:

0110101112 = 011 010 111 = 011(=3) 010(=2) 111(=7) = 3278

the Final answer: 110101112 = 3278

now let\'s make the transfer using the decimal system.

let\'s translate to decimal like this:

0∙28+1∙27+1∙26+0∙25+1∙24+0∙23+1∙22+1∙21+1∙20 = 0∙256+1∙128+1∙64+0∙32+1∙16+0∙8+1∙4+1∙2+1∙1 = 0+128+64+0+16+0+4+2+1 = 21510

got It: 0110101112 =21510

Translate the number 21510 в octal like this:

the Integer part of the number is divided by the base of the new number system:

2158
-208268
7-243
2
Перевод чисел из одной системы счисления в другую

the result of the conversion was:

21510 = 3278
the Final answer: 110101112 = 3278
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