Transfer 111100111010011101100010 from binary in octal number system

This transfer is possible in two ways: direct transfer and using the decimal system.

first, let\'s make a direct transfer.

let\'s make a direct translation from binary to post-binary like this:

111100111010011101100010₂ = 111 100 111 010 011 101 100 010 = 111₍₌₇₎ 100₍₌₄₎ 111₍₌₇₎ 010₍₌₂₎ 011₍₌₃₎ 101₍₌₅₎ 100₍₌₄₎ 010₍₌₂₎ = 74723542₈

the Final answer: 111100111010011101100010₂ = 74723542₈

now let\'s make the transfer using the decimal system.

let\'s translate to decimal like this:

1∙2²³+1∙2²²+1∙2²¹+1∙2²⁰+0∙2¹⁹+0∙2¹⁸+1∙2¹⁷+1∙2¹⁶+1∙2¹⁵+0∙2¹⁴+1∙2¹³+0∙2¹²+0∙2¹¹+1∙2¹⁰+1∙2⁹+1∙2⁸+0∙2⁷+1∙2⁶+1∙2⁵+0∙2⁴+0∙2³+0∙2²+1∙2¹+0∙2⁰ = 1∙8388608+1∙4194304+1∙2097152+1∙1048576+0∙524288+0∙262144+1∙131072+1∙65536+1∙32768+0∙16384+1∙8192+0∙4096+0∙2048+1∙1024+1∙512+1∙256+0∙128+1∙64+1∙32+0∙16+0∙8+0∙4+1∙2+0∙1 = 8388608+4194304+2097152+1048576+0+0+131072+65536+32768+0+8192+0+0+1024+512+256+0+64+32+0+0+0+2+0 = 15968098₁₀

got It: 111100111010011101100010₂ =15968098₁₀

Translate the number 15968098₁₀ в octal like this:

the Integer part of the number is divided by the base of the new number system: