This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
20.38 = 2 0. 3 = 2(=010) 0(=000). 3(=011) = 010000.0112
the Final answer: 20.38 = 10000.0112
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
2∙81+0∙80+3∙8-1 = 2∙8+0∙1+3∙0.125 = 16+0+0.375 = 16.37510
got It: 20.38 =16.37510
Translate the number 16.37510 в binary like this:
the Integer part of the number is divided by the base of the new number system:
16 | 2 | | | | |
-16 | 8 | 2 | | | |
0 | -8 | 4 | 2 | | |
| 0 | -4 | 2 | 2 | |
| | 0 | -2 | 1 | |
| | | 0 | | |
 |
the Fractional part of the number is multiplied by the base of the new number system:
 |
0. | 375*2 |
0 | .75*2 |
1 | .5*2 |
1 | .0*2 |
the result of the conversion was:
16.37510 = 10000.0112
the Final answer: 20.38 = 10000.0112