Transfer 0.1111111111111111 from binary in decimal number system

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let\'s translate to decimal like this:

0∙20+1∙2-1+1∙2-2+1∙2-3+1∙2-4+1∙2-5+1∙2-6+1∙2-7+1∙2-8+1∙2-9+1∙2-10+1∙2-11+1∙2-12+1∙2-13+1∙2-14+1∙2-15+1∙2-16 = 0∙1+1∙0.5+1∙0.25+1∙0.125+1∙0.0625+1∙0.03125+1∙0.015625+1∙0.0078125+1∙0.00390625+1∙0.001953125+1∙0.0009765625+1∙0.00048828125+1∙0.000244140625+1∙0.0001220703125+1∙6.103515625E-5+1∙3.0517578125E-5+1∙1.52587890625E-5 = 0+0.5+0.25+0.125+0.0625+0.03125+0.015625+0.0078125+0.00390625+0.001953125+0.0009765625+0.00048828125+0.000244140625+0.0001220703125+6.103515625E-5+3.0517578125E-5+1.52587890625E-5 = 0.9999847412109410

got It: 0.11111111111111112 =0.9999847412109410

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