Transfer B9f.1acb from hexadecimal in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

First we will perform the translation through the decimal system

let\'s translate to decimal like this:

11∙162+9∙161+15∙160+1∙16-1+10∙16-2+12∙16-3+11∙16-4 = 11∙256+9∙16+15∙1+1∙0.0625+10∙0.00390625+12∙0.000244140625+11∙1.52587890625E-5 = 2816+144+15+0.0625+0.0390625+0.0029296875+0.0001678466796875 = 2975.1046600341796910

got It: B9f.1acb16 =2975.1046600341796910

Translate the number 2975.1046600341796910 в octal like this:

the Integer part of the number is divided by the base of the new number system:

29758
-29683718
7-368468
3-405
6
Перевод чисел из одной системы счисления в другую

the Fractional part of the number is multiplied by the base of the new number system:

 Transferring numbers from one number system to another
0.10466003417969*8
0.83728*8
6.69824*8
5.58594*8
4.6875*8
5.5*8
4.0*8
5.0*8

the result of the conversion was:

2975.1046600341796910 = 5637.06545458
the Final answer: B9f.1acb16 = 5637.06545458

Now we will perform a direct translation.

let\'s do a direct translation from hexadecimal to binary like this:

B9f.1acb16 = B 9 f. 1 a c b = B(=1011) 9(=1001) f(=1111). 1(=0001) a(=1010) c(=1100) b(=1011) = 101110011111.00011010110010112

the Final answer: B9f.1acb16 = 101110011111.00011010110010112

Fill in the number with missing zeros on the right

let\'s make a direct translation from binary to post-binary like this:

101110011111.0001101011001011002 = 101 110 011 111. 000 110 101 100 101 100 = 101(=5) 110(=6) 011(=3) 111(=7). 000(=0) 110(=6) 101(=5) 100(=4) 101(=5) 100(=4) = 5637.0654548

the Final answer: B9f.1acb16 = 5637.0654548
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