This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
4∙82+7∙81+2∙80 = 4∙64+7∙8+2∙1 = 256+56+2 = 31410
got It: 4728 =31410
Translate the number 31410 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
314 | 16 | | |
-304 | 19 | 16 | |
A | -16 | 1 | |
| 3 | | |
|
the result of the conversion was:
31410 = 13A16
the Final answer: 4728 = 13A16
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
4728 = 4 7 2 = 4(=100) 7(=111) 2(=010) = 1001110102
the Final answer: 4728 = 1001110102
Fill in the number with missing zeros on the left
let\'s do a direct translation from binary to hexadecimal like this:
0001001110102 = 0001 0011 1010 = 0001(=1) 0011(=3) 1010(=A) = 13A16
the Final answer: 0001001110108 = 13A16