This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
10∙161+14∙160+7∙16-1+6∙16-2 = 10∙16+14∙1+7∙0.0625+6∙0.00390625 = 160+14+0.4375+0.0234375 = 174.460937510
got It: AE.7616 =174.460937510
Translate the number 174.460937510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
174 | 8 | | |
-168 | 21 | 8 | |
6 | -16 | 2 | |
| 5 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 4609375*8 |
3 | .6875*8 |
5 | .5*8 |
4 | .0*8 |
the result of the conversion was:
174.460937510 = 256.3548
the Final answer: AE.7616 = 256.3548
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
AE.7616 = A E. 7 6 = A(=1010) E(=1110). 7(=0111) 6(=0110) = 10101110.01110112
the Final answer: AE.7616 = 10101110.01110112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
010101110.0111011002 = 010 101 110. 011 101 100 = 010(=2) 101(=5) 110(=6). 011(=3) 101(=5) 100(=4) = 256.3548
the Final answer: AE.7616 = 256.3548