# Transfer 11.23 from octal in binary number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

first, let's make a direct transfer.

let's do a direct translation from octal to binary like this:

11.238 = 1 1. 2 3 = 1(=001) 1(=001). 2(=010) 3(=011) = 001001.0100112

the Final answer: 11.238 = 1001.0100112

now let's make the transfer using the decimal system.

let's translate to decimal like this:

1∙81+1∙80+2∙8-1+3∙8-2 = 1∙8+1∙1+2∙0.125+3∙0.015625 = 8+1+0.25+0.046875 = 9.29687510

got It: 11.238 =9.29687510

Translate the number 9.29687510 в binary like this:

the Integer part of the number is divided by the base of the new number system:

 9 2 -8 4 2 1 -4 2 2 0 -2 1 0 the Fractional part of the number is multiplied by the base of the new number system: 0. 296875*2 0 .59375*2 1 .1875*2 0 .375*2 0 .75*2 1 .5*2 1 .0*2

the result of the conversion was:

9.29687510 = 1001.0100112
the Final answer: 11.238 = 1001.0100112 