This transfer is possible in two ways: direct transfer and using the decimal system.
First we will perform the translation through the decimal system
let\'s translate to decimal like this:
1∙163+0∙162+10∙161+4∙160+2∙16-1+4∙16-2+6∙16-3 = 1∙4096+0∙256+10∙16+4∙1+2∙0.0625+4∙0.00390625+6∙0.000244140625 = 4096+0+160+4+0.125+0.015625+0.00146484375 = 4260.1420898437510
got It: 10A4.24616 =4260.1420898437510
Translate the number 4260.1420898437510 в octal like this:
the Integer part of the number is divided by the base of the new number system:
4260 | 8 | | | | |
-4256 | 532 | 8 | | | |
4 | -528 | 66 | 8 | | |
| 4 | -64 | 8 | 8 | |
| | 2 | -8 | 1 | |
| | | 0 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 14208984375*8 |
1 | .13672*8 |
1 | .09375*8 |
0 | .75*8 |
6 | .0*8 |
the result of the conversion was:
4260.1420898437510 = 10244.11068
the Final answer: 10A4.24616 = 10244.11068
Now we will perform a direct translation.
let\'s do a direct translation from hexadecimal to binary like this:
10A4.24616 = 1 0 A 4. 2 4 6 = 1(=0001) 0(=0000) A(=1010) 4(=0100). 2(=0010) 4(=0100) 6(=0110) = 1000010100100.001001000112
the Final answer: 10A4.24616 = 1000010100100.001001000112
Fill in the number with missing zeros on the left
Fill in the number with missing zeros on the right
let\'s make a direct translation from binary to post-binary like this:
001000010100100.0010010001102 = 001 000 010 100 100. 001 001 000 110 = 001(=1) 000(=0) 010(=2) 100(=4) 100(=4). 001(=1) 001(=1) 000(=0) 110(=6) = 10244.11068
the Final answer: 10A4.24616 = 10244.11068