Transfer 1101100101011110 from binary in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

first, let\'s make a direct transfer.

Fill in the number with missing zeros on the left

let\'s make a direct translation from binary to post-binary like this:

0011011001010111102 = 001 101 100 101 011 110 = 001(=1) 101(=5) 100(=4) 101(=5) 011(=3) 110(=6) = 1545368

the Final answer: 11011001010111102 = 1545368

now let\'s make the transfer using the decimal system.

let\'s translate to decimal like this:

0∙217+0∙216+1∙215+1∙214+0∙213+1∙212+1∙211+0∙210+0∙29+1∙28+0∙27+1∙26+0∙25+1∙24+1∙23+1∙22+1∙21+0∙20 = 0∙131072+0∙65536+1∙32768+1∙16384+0∙8192+1∙4096+1∙2048+0∙1024+0∙512+1∙256+0∙128+1∙64+0∙32+1∙16+1∙8+1∙4+1∙2+0∙1 = 0+0+32768+16384+0+4096+2048+0+0+256+0+64+0+16+8+4+2+0 = 5564610

got It: 0011011001010111102 =5564610

Translate the number 5564610 в octal like this:

the Integer part of the number is divided by the base of the new number system:

556468
-5564069558
6-69528698
3-8641088
5-104138
4-81
5
Перевод чисел из одной системы счисления в другую

the result of the conversion was:

5564610 = 1545368
the Final answer: 11011001010111102 = 1545368
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