This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
Fill in the number with missing zeros on the left
let\'s make a direct translation from binary to post-binary like this:
0011011001010111102 = 001 101 100 101 011 110 = 001(=1) 101(=5) 100(=4) 101(=5) 011(=3) 110(=6) = 1545368
the Final answer: 11011001010111102 = 1545368
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
0∙217+0∙216+1∙215+1∙214+0∙213+1∙212+1∙211+0∙210+0∙29+1∙28+0∙27+1∙26+0∙25+1∙24+1∙23+1∙22+1∙21+0∙20 = 0∙131072+0∙65536+1∙32768+1∙16384+0∙8192+1∙4096+1∙2048+0∙1024+0∙512+1∙256+0∙128+1∙64+0∙32+1∙16+1∙8+1∙4+1∙2+0∙1 = 0+0+32768+16384+0+4096+2048+0+0+256+0+64+0+16+8+4+2+0 = 5564610
got It: 0011011001010111102 =5564610
Translate the number 5564610 в octal like this:
the Integer part of the number is divided by the base of the new number system:
55646 | 8 | | | | | |
-55640 | 6955 | 8 | | | | |
6 | -6952 | 869 | 8 | | | |
| 3 | -864 | 108 | 8 | | |
| | 5 | -104 | 13 | 8 | |
| | | 4 | -8 | 1 | |
| | | | 5 | | |
|
the result of the conversion was:
5564610 = 1545368
the Final answer: 11011001010111102 = 1545368