This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s translate to decimal like this:
4∙83+0∙82+5∙81+7∙80+0∙8-1+6∙8-2 = 4∙512+0∙64+5∙8+7∙1+0∙0.125+6∙0.015625 = 2048+0+40+7+0+0.09375 = 2095.0937510
got It: 4057.068 =2095.0937510
Translate the number 2095.0937510 в hexadecimal like this:
the Integer part of the number is divided by the base of the new number system:
2095 | 16 | | |
-2080 | 130 | 16 | |
F | -128 | 8 | |
| 2 | | |
|
the Fractional part of the number is multiplied by the base of the new number system:
|
0. | 09375*16 |
1 | .5*16 |
8 | .0*16 |
the result of the conversion was:
2095.0937510 = 82F.1816
the Final answer: 4057.068 = 82F.1816
now let\'s make the transfer using the decimal system.
let\'s do a direct translation from octal to binary like this:
4057.068 = 4 0 5 7. 0 6 = 4(=100) 0(=000) 5(=101) 7(=111). 0(=000) 6(=110) = 100000101111.0001102
the Final answer: 4057.068 = 100000101111.000112
Fill in the number with missing zeros on the right
let\'s do a direct translation from binary to hexadecimal like this:
100000101111.000110002 = 1000 0010 1111. 0001 1000 = 1000(=8) 0010(=2) 1111(=F). 0001(=1) 1000(=8) = 82F.1816
the Final answer: 100000101111.000110008 = 82F.1816