# Transfer 11011100.101010 from binary in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

first, let\'s make a direct transfer.

Fill in the number with missing zeros on the left

let\'s make a direct translation from binary to post-binary like this:

011011100.1010102 = 011 011 100. 101 010 = 011(=3) 011(=3) 100(=4). 101(=5) 010(=2) = 334.528

the Final answer: 11011100.1010102 = 334.528

now let\'s make the transfer using the decimal system.

let\'s translate to decimal like this:

0∙28+1∙27+1∙26+0∙25+1∙24+1∙23+1∙22+0∙21+0∙20+1∙2-1+0∙2-2+1∙2-3+0∙2-4+1∙2-5+0∙2-6 = 0∙256+1∙128+1∙64+0∙32+1∙16+1∙8+1∙4+0∙2+0∙1+1∙0.5+0∙0.25+1∙0.125+0∙0.0625+1∙0.03125+0∙0.015625 = 0+128+64+0+16+8+4+0+0+0.5+0+0.125+0+0.03125+0 = 220.6562510

got It: 011011100.1010102 =220.6562510

Translate the number 220.6562510 в octal like this:

the Integer part of the number is divided by the base of the new number system:

 220 8 -216 27 8 4 -24 3 3 the Fractional part of the number is multiplied by the base of the new number system: 0. 65625*8 5 .25*8 2 .0*8

the result of the conversion was:

220.6562510 = 334.528
the Final answer: 11011100.1010102 = 334.528
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