# Transfer 10110110.010101 from binary in octal number system

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This transfer is possible in two ways: direct transfer and using the decimal system.

first, let\'s make a direct transfer.

Fill in the number with missing zeros on the left

let\'s make a direct translation from binary to post-binary like this:

010110110.0101012 = 010 110 110. 010 101 = 010(=2) 110(=6) 110(=6). 010(=2) 101(=5) = 266.258

the Final answer: 10110110.0101012 = 266.258

now let\'s make the transfer using the decimal system.

let\'s translate to decimal like this:

0∙28+1∙27+0∙26+1∙25+1∙24+0∙23+1∙22+1∙21+0∙20+0∙2-1+1∙2-2+0∙2-3+1∙2-4+0∙2-5+1∙2-6 = 0∙256+1∙128+0∙64+1∙32+1∙16+0∙8+1∙4+1∙2+0∙1+0∙0.5+1∙0.25+0∙0.125+1∙0.0625+0∙0.03125+1∙0.015625 = 0+128+0+32+16+0+4+2+0+0+0.25+0+0.0625+0+0.015625 = 182.32812510

got It: 010110110.0101012 =182.32812510

Translate the number 182.32812510 в octal like this:

the Integer part of the number is divided by the base of the new number system:

 182 8 -176 22 8 6 -16 2 6 the Fractional part of the number is multiplied by the base of the new number system: 0. 328125*8 2 .625*8 5 .0*8

the result of the conversion was:

182.32812510 = 266.258
the Final answer: 10110110.0101012 = 266.258
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