This transfer is possible in two ways: direct transfer and using the decimal system.
first, let\'s make a direct transfer.
let\'s do a direct translation from octal to binary like this:
325.24_{8} = 3 2 5. 2 4 = 3_{(=011)} 2_{(=010)} 5_{(=101)}. 2_{(=010)} 4_{(=100)} = 011010101.010100_{2}
the Final answer: 325.24_{8} = 11010101.0101_{2}
now let\'s make the transfer using the decimal system.
let\'s translate to decimal like this:
3∙8^{2}+2∙8^{1}+5∙8^{0}+2∙8^{1}+4∙8^{2} = 3∙64+2∙8+5∙1+2∙0.125+4∙0.015625 = 192+16+5+0.25+0.0625 = 213.3125_{10}
got It: 325.24_{8} =213.3125_{10}
Translate the number 213.3125_{10} в binary like this:
the Integer part of the number is divided by the base of the new number system:
213  2        
212  106  2       
1  106  53  2      
 0  52  26  2     
  1  26  13  2    
   0  12  6  2   
    1  6  3  2  
     0  2  1  
      1   

the Fractional part of the number is multiplied by the base of the new number system:

0.  3125*2 
0  .625*2 
1  .25*2 
0  .5*2 
1  .0*2 
the result of the conversion was:
213.3125_{10} = 11010101.0101_{2}
the Final answer: 325.24_{8} = 11010101.0101_{2}